0=5x^2+500x

Solution for 0=5x^2+500x equation:

0=5x^2+500x

We move all terms to the left:

0-(5x^2+500x)=0

We add all the numbers together, and all the variables

-(5x^2+500x)=0

We get rid of parentheses

-5x^2-500x=0

a = -5; b = -500; c = 0;
Δ = b2-4ac
Δ = -5002-4·(-5)·0
Δ = 250000
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{250000}=500$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-500)-500}{2*-5}=\frac{0}{-10}
=0
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-500)+500}{2*-5}=\frac{1000}{-10}
=-100
$